4[x+3(x-2)]+1=5

Solution for 4[x+3(x-2)]+1=5 equation:

Simplifying
4[x + 3(x + -2)] + 1 = 5

Reorder the terms:
4[x + 3(-2 + x)] + 1 = 5
4[x + (-2 * 3 + x * 3)] + 1 = 5
4[x + (-6 + 3x)] + 1 = 5

Reorder the terms:
4[-6 + x + 3x] + 1 = 5

Combine like terms: x + 3x = 4x
4[-6 + 4x] + 1 = 5
[-6 * 4 + 4x * 4] + 1 = 5
[-24 + 16x] + 1 = 5

Reorder the terms:
-24 + 1 + 16x = 5

Combine like terms: -24 + 1 = -23
-23 + 16x = 5

Solving
-23 + 16x = 5

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '23' to each side of the equation.
-23 + 23 + 16x = 5 + 23

Combine like terms: -23 + 23 = 0
0 + 16x = 5 + 23
16x = 5 + 23

Combine like terms: 5 + 23 = 28
16x = 28

Divide each side by '16'.
x = 1.75

Simplifying
x = 1.75